Evaluate Algebraic Expression (ax+b)/(ax-b)

#include<stdio.h>
#include<conio.h>
main()
{
    int a,b,x;
    float s;
    printf("Enter the Values of a,b,x...");
    scanf("%d%d%d",&a,&b,&x);
    s=(a*x+b)/(a*x-b);
    printf("The Resultant Value is : %f",s);
    
}

 OUTPUT:

Enter the Values of a,b,x...2 3 5
The Resultant Value is : 1.000000

ALGORITHM:

Step1: Start
Step2: Input a,b,x,s
Step3: s= (a*x+b)/(a*x-b)
Step4: Result s
Step5: Stop